0=4x^2-x-62

Solution for 0=4x^2-x-62 equation:

0=4x^2-x-62

We move all terms to the left:

0-(4x^2-x-62)=0

We add all the numbers together, and all the variables

-(4x^2-x-62)=0

We get rid of parentheses

-4x^2+x+62=0

a = -4; b = 1; c = +62;
Δ = b2-4ac
Δ = 12-4·(-4)·62
Δ = 993
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{993}}{2*-4}=\frac{-1-\sqrt{993}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{993}}{2*-4}=\frac{-1+\sqrt{993}}{-8}
$